# How do you set up an integral from the length of the curve #y=1/x, 1<=x<=5#?

##### 1 Answer

Feb 25, 2017

#### Explanation:

The length of the curve of

#L=int_a^bsqrt(1+(dy/dx)^2)#

For

#L=int_1^5sqrt(1+(-1/x^2)^2)=int_1^5sqrt(1+1/x^4)#

Which can be plugged into a calculator for a result of